Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
27/5 = 5 remainder 2
no. The remainder should be less than the divisor. If you get a remainder of 5 and did not make any other mistake, add one to the quotient and the remainder will be 1.
5
zero
you can do divide 83 and 5 and that will be your biggest remainder.
The largest integer remainder is 6.
Yes, you can have a remainder of 5 when you divide by 6. If you divide 11 by 6, it will go into it one time with a remainder of 5.
The largest remainder when dividing by 6 is 5. This is true because if the remainder is 6, the 6 would divide into the number again. For example: 35 divided by 6 is 5 remainder 5. 36 divided by 6 cannot be 5 remainder 6 because 6 will divide into 36 again. The answer would be 6.
Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
27/5 = 5 remainder 2
122.2381
no. The remainder should be less than the divisor. If you get a remainder of 5 and did not make any other mistake, add one to the quotient and the remainder will be 1.
To find the number, we need to consider the remainders when the number is divided by 5 and 4. Let's denote the number as x. From the information given, we have two equations: x ≡ 1 (mod 5) and x ≡ 2 (mod 4). By solving these congruences simultaneously using the Chinese Remainder Theorem, we find that x ≡ 21 (mod 20). Therefore, the number you are thinking of is 21.
5
any number between 0 and 9.
Yes - any number one fewer than a multiple of 6 will give a remainder of 5. For example, 11/6 = 1 remainder 5. 17/6 = 2 remainder 5.