Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
27/5 = 5 remainder 2
no. The remainder should be less than the divisor. If you get a remainder of 5 and did not make any other mistake, add one to the quotient and the remainder will be 1.
5
zero
Well, darling, when you divide any number by 5, the largest remainder you can get is 4. Why? Because when you divide by 5, the remainders can only be 0, 1, 2, 3, or 4. So, if you wanna keep it simple and sassy, the largest remainder with a divisor of 5 is 4.
The largest integer remainder is 6.
Yes, you can have a remainder of 5 when you divide by 6. If you divide 11 by 6, it will go into it one time with a remainder of 5.
The largest remainder when dividing by 6 is 5. This is true because if the remainder is 6, the 6 would divide into the number again. For example: 35 divided by 6 is 5 remainder 5. 36 divided by 6 cannot be 5 remainder 6 because 6 will divide into 36 again. The answer would be 6.
Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
27/5 = 5 remainder 2
no. The remainder should be less than the divisor. If you get a remainder of 5 and did not make any other mistake, add one to the quotient and the remainder will be 1.
5
any number between 0 and 9.
Yes - any number one fewer than a multiple of 6 will give a remainder of 5. For example, 11/6 = 1 remainder 5. 17/6 = 2 remainder 5.
When you divide by 5, the remainder can be 0, 1, 2, 3, or 4, but no more than 4.
32 divided by 5 is 6 with remainder 2.