Algebraically, 3T + 4W = 36 where T and W are non-negative integers. T = 0 W = 9 T = 4 W = 6 T = 8 W = 3 T = 12 W = 0
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No. 36 is a multiple of 12, and 12 is a factor of 36.
-24 + 12 = -12
36 is the least common multiple of 36 and 12.
Algebraically, 3T + 4W = 36 where T and W are non-negative integers. T = 0 W = 9 T = 4 W = 6 T = 8 W = 3 T = 12 W = 0
It depends on the value of w. w < 6 then 6w < 36 w = 6 then 6w = 36 and w > 6 then 6w >36
To solve this problem, you first need to define some variables and then set up an equation. Let w = width of the rectangle and l = length of the rectangle. Since the length is 9 m longer than the width, we can write the following: w = width w + 9 = length Since the area of a rectangle is found by multiplying length x width, we can write the following equation: w(w + 9) = 36 Next, we must solve this equation. By the distributive property, we have w^2 + 9w = 36. Subtracting 36 from both sides, we get w^2 + 9w - 36 = 0 We can factor this trinomial into (w + 12)(w - 3) = 0 By the zero product property, we have w + 12 = 0 or w - 3 = 0 Solving these two equations, we have that w = -12 or w = 3. Since the width of a rectangle cannot be negative, we ignore the w = -12 solution and we find that w = 3. Since our width is 3 m, our length must be 12 m. We can check our answer by verifying that 12 m x 3m = 36 m^2.
63° 37′ 12″ n, 19° 36′ 48″ w
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all the multiples of 36 (because 6 goes into 36 w/o remainder) 36, 72, 108, 144, etc.
34˚ 36' 12" s , 58˚ 22' 54" w
William is 12, his uncle is 36. When William is 24, his uncle will be 48. Algebraically: U = 3W U + 12 = 2 (W +12) Substituting: (3W) + 12 = 2 (W + 12) 3W + 12 = 2W + 24 W = 12
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
The longitude and latitude for Boise, Idaho is 43°36′49″N by 116°12′12″W
34° 36′ 12″ S, 58° 22′ 54″ W-34.603333, -58.381667
12% as a fraction of 36 = 12/36