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Look for numbers that multiply to be 14, and add(or subtract) to be 5). In this case you want subtraction, since the x2 is negative. If you cannot figure out the factors, use the quadratic formula:
For ax2 + bx + c:
[-b +/- sqrt(b2 -4ac)] / (2a) = [-5 +/- sqrt(52 -4*(-1)*14)] / (-2) = 5/2 +/- sqrt(81)/2
= 5/2 +/- 9/2 --> 14/2 & -4/2 --> 7 & -2.
so this would factor to (-1)*(x - 7)*(x + 2) = (-x + 7)*(x + 2)
Note that 7*2=14 and 7x - 2x = 5x.
What else can I help you with?
Factor x2 plus 5x-120?
x2 + 5x - 120 can not be factored.
How do you factor th trinomial -x2 plus 5x plus 14?
-(x - 7)(x + 2)
How do you factor 5x squared plus 5x plus 5?
5(x2 + x + 1)
What are the factors of the polynomial x2 plus 5x - 14?
x2+5x-14 = (x+7)(x-2) when factored
Which of the binomials below is a factor of this trinomial x2 plus 5x plus 6?
x2+5x+6 = (x+2)(x+3)
What is the binomials is a factor of this trinomial x2 -5x plus 4?
x2-5x+4 = (x-1)(x-4) when factored
How do you factor x2 plus 5X-6 into two binomials?
x2+5x-6 = (x+6)(x-1) when factored
-x2 plus 5x plus 14?
-(x - 7)(x + 2)
When the expressions x2 9 and x2 5x plus 6 are factored a common factor is?
x - 3
Factor x2 plus 5x plus 6 equals 0?
You don't factor an equation. You factor an expression.So we'll forget about the "equals 0" for a second, while we factor "x2 plus 5x plus 6".x2 + 5x + 6 = (x + 3) (x + 2).Now, if you want this expression to be equal to zero, that can only happen when 'x' is -2 or -3.
Which of the binomials below is factor of this trinomial x2-5x plus 4 equals?
x2-5x+4 = (x-1)(x-4) when factord
Factor x2 plus 5x - 24?
(x + 8)(x - 3)
