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2x2 - 5x - 3 = 0

The coefficients here are (2,-5,-3) so you want two numbers whose multiple is 2*(-3) = -6 and whose sum is -5. The numbers are 1 and -6.

So 2x2 - 6x + x - 3 = 0

2x(x-3) + 1(x-3) = 0

(2x+1)*(x-3) = 0

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15y ago

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