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Q: What is the answer to factor the following polynomial x to the second power minus one?

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8x2-3x-5 = (8x+5)(x-1) when factored

5a2-15 = 5 (a2-3) = 5 (a-sqrt(3))(a+sqrt(3)) as a2-b2=(a-b)(a+b)

It is x minus the complex conjugate of the first root. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols and so it is not possible to make out what the factor given in the question is. It is therefore impossible to give a proper answer to your question. In future please submit your question spelling out the symbols as "plus", "minus".

(x + 1)(x - 8)

(x - 2)(2x + 3)

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8x2-3x-5 = (8x+5)(x-1) when factored

(x - 12)(x - 7)

which of the following is a factor of x2 - 5x - 6

X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.

For a start, you can look for a common factor, and separate it. What remains (the other factor) will only be a polynomial of degree 2; I assume you already learned how to factor that.

Depending on the missing operational sign, that would be 2(x plus or minus 8)

A 7th degree polynomial.

Yes, it is a linear polynomial.

Depending on the missing operational sign, that would be 2(x plus or minus 8)

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