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First change all the dimensions into cm and then mark out each vertex as A B C and mark out the opposites of these as a b c. Then by using the cosine rule:

Cos A = (b2+c2-a2) over 2bc = 32.54064077 degrees

Cos B = (a2+c2-b2) over 2ac = 46.98748283 degrees

Cos C = (a2+b2-c2) over 2ab = 100.4718764 degrees

Having found the first angle it is possible to find the other angles by using the sine rule or having found the first and second angle subtract these angles from 180 to find the third angle.

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Q: How do you find in detail the interior angles of a triangle that has sides of 2.34 m and 128 cm with a base of 1740 mm?
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