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Assuming the simple model where the object is projected with an initial velocity of u metres/second at an angle of x to the horizontal, and that the only force acting on it after that is gravitational acceleration, g = 9.81 metres/second^2, then h = [u*sin(x)]^2/(2*g) metres.

If the launch is vertical then x = pi/2 radians and h = u^2/(2*g) metres.

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9y ago
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9y ago

A projectile reaches its maximum height when the vertical velocity , Vy , is zero. Basic kinematics
gives :

ymax = ( Vy0 )^2 / ( 2 ) ( g )

where Vy0 is the initial vertical velocity and g is the gravitational acceleration.

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