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You cannot: there is not enough information.

You cannot: there is not enough information.

You cannot: there is not enough information.

You cannot: there is not enough information.

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You cannot: there is not enough information.

Q: How do you find percentage using mean and standard deviation?

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You cannot because the median of a distribution is not related to its standard deviation.

100 x (standard deviation/mean)

You're an idiot. It's standard deviation. Google that for your answer.

8.919280881 is the standard deviation for those numbers.

It is mean + 2*standard deviation.

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You cannot because the median of a distribution is not related to its standard deviation.

100 x (standard deviation/mean)

Information is not sufficient to find mean deviation and standard deviation.

we calculate standard deviation to find the avg of the difference of all values from mean.,

No, you have it backwards, the standard deviation is the square root of the variance, so the variance is the standard deviation squared. Usually you find the variance first, as it is the average sum of squares of the distribution, and then find the standard deviation by squaring it.

The answer depends on what functions are built into your calculator. Read the calculator manual.

1242

You're an idiot. It's standard deviation. Google that for your answer.

A standard deviation calculator allows the user to find the mean spread away from the mean in a statistical environment. Most users needing to find the standard deviation are in the statistics field. Usually, the data set will be given and must be typed into the calculator. The standard deviation calculator will then give the standard deviation of the data. In order to find the variance of the data, simply square the answer.

If the population standard deviation is sigma, then the estimate for the sample standard error for a sample of size n, is s = sigma*sqrt[n/(n-1)]

Look at the Wikipedia article on "Standard deviation" - it includes an example right at the beginning.

Standard deviation calculation is somewhat difficult.Please refer to the site below for more info