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If the three-dimensional figure is bounded by polygons, you calculate the area of each polygon, and add it all up. If the three-dimensional figure is bounded by some curve (as in a sphere), you basically need integral calculus. The basic idea is to divide the surface into small pieces, assume that each piece is approximately equal to a rectangle, triangle, or another convenient (and well-known) 2D figure, and add the surface areas up. Also, you analyze what happens when the individual pieces are made smaller and smaller. Integral calculus has some special methods to speed this task up, but that is the basic idea.
If the three-dimensional figure is bounded by polygons, you calculate the area of each polygon, and add it all up. If the three-dimensional figure is bounded by some curve (as in a sphere), you basically need integral calculus. The basic idea is to divide the surface into small pieces, assume that each piece is approximately equal to a rectangle, triangle, or another convenient (and well-known) 2D figure, and add the surface areas up. Also, you analyze what happens when the individual pieces are made smaller and smaller. Integral calculus has some special methods to speed this task up, but that is the basic idea.
If the three-dimensional figure is bounded by polygons, you calculate the area of each polygon, and add it all up. If the three-dimensional figure is bounded by some curve (as in a sphere), you basically need integral calculus. The basic idea is to divide the surface into small pieces, assume that each piece is approximately equal to a rectangle, triangle, or another convenient (and well-known) 2D figure, and add the surface areas up. Also, you analyze what happens when the individual pieces are made smaller and smaller. Integral calculus has some special methods to speed this task up, but that is the basic idea.
If the three-dimensional figure is bounded by polygons, you calculate the area of each polygon, and add it all up. If the three-dimensional figure is bounded by some curve (as in a sphere), you basically need integral calculus. The basic idea is to divide the surface into small pieces, assume that each piece is approximately equal to a rectangle, triangle, or another convenient (and well-known) 2D figure, and add the surface areas up. Also, you analyze what happens when the individual pieces are made smaller and smaller. Integral calculus has some special methods to speed this task up, but that is the basic idea.
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DevinIf the three-dimensional figure is bounded by polygons, you calculate the area of each polygon, and add it all up. If the three-dimensional figure is bounded by some curve (as in a sphere), you basically need integral calculus. The basic idea is to divide the surface into small pieces, assume that each piece is approximately equal to a rectangle, triangle, or another convenient (and well-known) 2D figure, and add the surface areas up. Also, you analyze what happens when the individual pieces are made smaller and smaller. Integral calculus has some special methods to speed this task up, but that is the basic idea.
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How does knowing the area of two-dimensional figures help you find the surface area of a three-dimensional shape?
The surface area of the 3-D figure will be the total of the areas of the 2-D figures.
How do you find the area of a binomial?
A binomial is an algebraic expression. It does not have an area.
How do you find the perimeter and area of irregular figures with irregular sizes of squares?
by subtracting
What are the basic formula of plane figures?
Different figures have different formulae; here you will find formulae for the areas of some figures: http://en.wikipedia.org/wiki/Area#Formulae
Area and perimeter of plane figures?
the area and perimeter of the plane figures are square ,rectangle
