answersLogoWhite

0

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

User Avatar

Wiki User

11y ago

Still curious? Ask our experts.

Chat with our AI personalities

TaigaTaiga
Every great hero faces trials, and you—yes, YOU—are no exception!
Chat with Taiga
FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
ProfessorProfessor
I will give you the most educated answer.
Chat with Professor
More answers

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

User Avatar

Wiki User

11y ago
User Avatar

Add your answer:

Earn +20 pts
Q: How do you find the rule in a linear table of values?
Write your answer...
Submit
Still have questions?
magnify glass
imp