0

# How do you find the rule in a linear table of values?

Updated: 12/15/2022

Wiki User

10y ago

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.

Wiki User

10y ago

Wiki User

10y ago

First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.

So, given that there at at least two sets of data, suppose they are as follows:

x1 gets mapped to y1

and

x2 gets mapped to y2

Then calculate m = (y2-y1)/(x2-x1)

and c = y - mx for any x-y combination from the table.

The rule is y = mx + c.