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Equation 1: y = x-3 => y2 = 3y2-18x+27 when both sides are squared and multiplied by 3
Equation 2: x2-3y2 = k => x2-k = 3y2 => 3y2 = x2 -k
By definition:
3x2-18x+27 = x2-k => 2x2-18x+27+k = 0
Use the discriminant b2-4ac = 0 to find the value of k:
b2-4ac = 0 => 182-4*2*(27+k) = 0
108-8k = 0
-8k = -108
k = 13.5
Check: 182-4*2*(27+13.5) = 0
k = 0.1
2
the shape of the curve skewed is "right"
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2
If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)
It is (-0.3, 0.1)
k = 0.1
2
the shape of the curve skewed is "right"
If the line y = 2x+1.25 is a tangent to the curve y^2 = 10x then it works out that when x = 5/8 then y = 5/2
If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)
-2
14.2
4 squared is 4 x 4 which equals 16.
Because the value of C equals 13
If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.
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