multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
the time period of a pendulum is proportional to the square root of length.if the length of the pendulum is increased the time period of the pendulum also gets increased. we know the formula for the time period , from there we can prove that the time period of a pendulum is directly proportional to the effective length of the pendulum. T=2 pi (l\g)^1\2 or, T isproportionalto (l/g)^1/2 or, T is proportional to square root of the effective length.
time period of simple pendulum is dirctly proportional to sqare root of length...
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
The time period of a simple pendulum is determined by the length of the pendulum, the acceleration due to gravity, and the angle at which the pendulum is released. The formula for the time period of a simple pendulum is T = 2Οβ(L/g), where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
Doubling the mass of a pendulum will not affect the time period of its oscillation. The time period of a pendulum depends on the length of the pendulum and the acceleration due to gravity, but not on the mass of the pendulum bob.
The time period of a pendulum is directly proportional to the square root of its length. If the length of the pendulum is increased, the time period will also increase. Conversely, if the length is decreased, the time period will decrease.
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
The time period of a simple pendulum depends only on the length of the pendulum and the acceleration due to gravity, not the mass of the pendulum bob. This is because the mass cancels out in the equation for the time period, leaving only the factors that affect the motion of the pendulum.
The time period of a pendulum is determined by its length and gravitational acceleration. If the length of the second pendulum is one third of the original pendulum, its time period would be shorter since the time period is directly proportional to the square root of the length.
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
the period
The period of a pendulum that takes 1 second is also 1 second. The period of a pendulum is the time it takes to complete one full swing back and forth.
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
the time period of a pendulum is proportional to the square root of length.if the length of the pendulum is increased the time period of the pendulum also gets increased. we know the formula for the time period , from there we can prove that the time period of a pendulum is directly proportional to the effective length of the pendulum. T=2 pi (l\g)^1\2 or, T isproportionalto (l/g)^1/2 or, T is proportional to square root of the effective length.
The time period of a simple pendulum is not affected by the mass of the bob, as long as the amplitude of the swing remains small. So, doubling the mass of the bob will not change the time period of the pendulum.