The equation of the line will be y = 2/5x and by creating coordinates in terms of x and y a straight line can then be graphed.
the slope is 1, and goes through the origin. It's a straight, diagonal line.
The slope for a straight line graph is the ratio of the amount by which the graph goes up (the rise) for every unit that it goes to the right (the run). If the graph goes down, the slope is negative. For a curved graph, the gradient at any point is the slope of the tangent to the graph at that point.
It makes a line ,it goes through the origin, it has a constant
To find a unit rate on a graph that goes through the origin, identify the coordinates of a point on the line (other than the origin). The unit rate is determined by calculating the slope of the line, which is the change in the y-value divided by the change in the x-value (rise over run). Since the line passes through the origin, the slope directly represents the unit rate of change between the two quantities. For example, if the point is (4, 8), the unit rate would be 8/4 = 2, indicating that for every 1 unit increase in x, y increases by 2 units.
5. if there is a line that says for instance y= 5x the answer on how to graph it would be the slope is the fraction. How far it "rises" on the graph, over how far it "runs" goes to the right or left. ( the answer is 5/1 or it rises 5 spaces on the graph and it goes to the right one) If a slope is negative it goes to the left. Also if it was y= 5x +3 it would do the same thing as before, but instead of starting from the origin (0,0) it would start at +3 and go from there.
the slope is 1, and goes through the origin. It's a straight, diagonal line.
The slope for a straight line graph is the ratio of the amount by which the graph goes up (the rise) for every unit that it goes to the right (the run). If the graph goes down, the slope is negative. For a curved graph, the gradient at any point is the slope of the tangent to the graph at that point.
You start at the origin and go down 4, forward one. Continue doing that. Then, go up 4, back 1 starting back at the origin. Continue doing that.
4y = 3xDivide each side by 4:y = (3/4) xThe slope of the graph is (3/4).The y-intercept is zero. (The line goes through the origin.)
It makes a line ,it goes through the origin, it has a constant
For example, if the slope at a certain point is 1.5, you can draw a line that goes through the specified point, with that slope. The line would represent the slope at that point. If you want to graph the slope at ALL POINTS, take the derivative of the function, and graph the derivative. The derivative shows the slope of a function at all points.
It may or may not exist. Whether or not the graph goes through the origin does not in any way affect whether or not it has a derivative. A function has a derivative if it has no discontinuities, cusps, sharp corners, or vertical tangents.
To find a unit rate on a graph that goes through the origin, identify the coordinates of a point on the line (other than the origin). The unit rate is determined by calculating the slope of the line, which is the change in the y-value divided by the change in the x-value (rise over run). Since the line passes through the origin, the slope directly represents the unit rate of change between the two quantities. For example, if the point is (4, 8), the unit rate would be 8/4 = 2, indicating that for every 1 unit increase in x, y increases by 2 units.
5. if there is a line that says for instance y= 5x the answer on how to graph it would be the slope is the fraction. How far it "rises" on the graph, over how far it "runs" goes to the right or left. ( the answer is 5/1 or it rises 5 spaces on the graph and it goes to the right one) If a slope is negative it goes to the left. Also if it was y= 5x +3 it would do the same thing as before, but instead of starting from the origin (0,0) it would start at +3 and go from there.
no
It's a slanted straight line that goes through the origin of the coordinates.
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).