It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
It makes a line ,it goes through the origin, it has a constant
no
the slope is 1, and goes through the origin. It's a straight, diagonal line.
To find a unit rate on a graph that goes through the origin, identify the coordinates of a point on the line (other than the origin). The unit rate is determined by calculating the slope of the line, which is the change in the y-value divided by the change in the x-value (rise over run). Since the line passes through the origin, the slope directly represents the unit rate of change between the two quantities. For example, if the point is (4, 8), the unit rate would be 8/4 = 2, indicating that for every 1 unit increase in x, y increases by 2 units.
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
It makes a line ,it goes through the origin, it has a constant
It may or may not exist. Whether or not the graph goes through the origin does not in any way affect whether or not it has a derivative. A function has a derivative if it has no discontinuities, cusps, sharp corners, or vertical tangents.
Divide the ordinate (y-coord) of any point on the graph by its abscissa (x-coord).
no
It's a slanted straight line that goes through the origin of the coordinates.
goes through the origin, up and to the right
the slope is 1, and goes through the origin. It's a straight, diagonal line.
To find a unit rate on a graph that goes through the origin, identify the coordinates of a point on the line (other than the origin). The unit rate is determined by calculating the slope of the line, which is the change in the y-value divided by the change in the x-value (rise over run). Since the line passes through the origin, the slope directly represents the unit rate of change between the two quantities. For example, if the point is (4, 8), the unit rate would be 8/4 = 2, indicating that for every 1 unit increase in x, y increases by 2 units.
-- Take the equation -- Set either 'x' or 'y' equal to zero -- Solve the resulting equation for the remaining variable -- If the remaining variable is then also zero, then the origin is on the graph of the function If the graph is a straight line ('x' and 'y' appear in the equation only to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin.
No, in general, the force vs acceleration graph does not always pass through the origin. This is because there may be a non-zero force acting on an object even when it is at rest. The presence of a non-zero force at rest would lead to a non-zero intercept on the force vs acceleration graph.
It is in quadrants 1 and 2 It is v shaped it goes through the origin hope this helps!
You start at the origin and go down 4, forward one. Continue doing that. Then, go up 4, back 1 starting back at the origin. Continue doing that.