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How can you find the unit rate on a graph that goes through the origin?
Kimberlyskyegp2450
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
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How do you know when a graph is proportional?
It makes a line ,it goes through the origin, it has a constant
Should the line of a normal force vs static friction graph pass through the origin Same goes for kinetic friction graph?
no
How do you graph the linear equation x equals y?
the slope is 1, and goes through the origin. It's a straight, diagonal line.
What is a linear function that goes through the origin?
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
The equation y ax describes the graph of a line If the value of a is positive the line?
Goes from the origin to the North East (up and to the right).
How do you know when a graph is proportional?
It makes a line ,it goes through the origin, it has a constant
Does a derivative exist if the graph goes through the origin?
It may or may not exist. Whether or not the graph goes through the origin does not in any way affect whether or not it has a derivative. A function has a derivative if it has no discontinuities, cusps, sharp corners, or vertical tangents.
How can you find the unit rate on a gragh that goes through the origin?
Divide the ordinate (y-coord) of any point on the graph by its abscissa (x-coord).
Should the line of a normal force vs static friction graph pass through the origin Same goes for kinetic friction graph?
no
What does a graph of a proportional relationship look like?
It's a slanted straight line that goes through the origin of the coordinates.
The equation y equals ax describes the graph of a line If the value of a is positive the line?
goes through the origin, up and to the right
How do you graph the linear equation x equals y?
the slope is 1, and goes through the origin. It's a straight, diagonal line.
How does one find out if an equation's graph goes through the origin?
-- Take the equation -- Set either 'x' or 'y' equal to zero -- Solve the resulting equation for the remaining variable -- If the remaining variable is then also zero, then the origin is on the graph of the function If the graph is a straight line ('x' and 'y' appear in the equation only to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin.
Does the force vs acceleration graph goes through origin?
No, in general, the force vs acceleration graph does not always pass through the origin. This is because there may be a non-zero force acting on an object even when it is at rest. The presence of a non-zero force at rest would lead to a non-zero intercept on the force vs acceleration graph.
What are characteristics of the graph of the absolute value parent function in geometry?
It is in quadrants 1 and 2 It is v shaped it goes through the origin hope this helps!
How do you Graph the line that goes through the origin and has slope -4?
You start at the origin and go down 4, forward one. Continue doing that. Then, go up 4, back 1 starting back at the origin. Continue doing that.
Why is it important always to draw a line through the origin when you are making a graph?
It isn't. In fact, it's vital that you only do it when it's appropriate to do so. If a graph goes through the origin, that means the point (0,0) belongs on the line. In many cases it does, but in others it doesn't. Ask yourself what your graph means. Is one variable equal to zero when the other one is? Suppose you are plotting the temperature of a hot cup of tea, starting from the time you pour it. At time zero, the temperature will not be zero degrees celsius. It will be much higher. It is the same with mathematical graphs. y = x squared goes through the origin, but y = x squared + 1 does not.
