y = 5x3 + 5 is a cubic equation. You cannot solve for x (or y), because there are two variables and only one equation. If you graph this, however, you will see a curve that passes through all possible points that make this equality true.
y = 5x3 + 6 is a cubic equation, not a linear equation. Linear equations contain only terms of degree 0 (i.e. constants) and terms of degree 1.
The graph shifts downward (negative y) by 9 units.
3
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
y = 5x3 + 5 is a cubic equation. You cannot solve for x (or y), because there are two variables and only one equation. If you graph this, however, you will see a curve that passes through all possible points that make this equality true.
No translation will invert a quadratic graph.
y = 5x3 + 6 is a cubic equation, not a linear equation. Linear equations contain only terms of degree 0 (i.e. constants) and terms of degree 1.
The graph shifts downward (negative y) by 9 units.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
y= -5
3
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
y=x+1 there for answer is 2
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
-7
12