-8
Y- intercept of 4x+8y=16
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
If y = 2, then 8y = 8 x 2 = 16.
y = -1
(0,2)
16
Solve for Y algebraically. 4X + 8Y = 16 8Y = - 4X + 16 Y = - 1/2X + 2 graph and see that the Y intercept = 2
Y- intercept of 4x+8y=16
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
If y = 2, then 8y = 8 x 2 = 16.
To solve for y, divide both sides of the equation by -0.8.
16 - 8y = 4xIt is a straight line equation. Graphically, the line two intercept points are:(0, 2) and (4,0)
y = -1
(0,2)
To find the y-intercept of the equation (4x - 8y = 16), we set (x = 0). Substituting (x = 0) into the equation gives (4(0) - 8y = 16), which simplifies to (-8y = 16). Dividing both sides by -8, we find (y = -2). Thus, the y-intercept is ((0, -2)).
x = 12 and y = 8
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4