You can't SOLVE something unless it's an EQUATION. So let's assume you mean the equation
6x² plus 6x plus 6 equals zero (a standard form for equations)
6x² + 6x + 6 = 0
same as
x² + x + 1 = 0 (div both sides by 6)
so
x² + x = -1
Now we can complete the square on THAT thing
x² + x + 1/2 = -1 + 1/2
(x + 1/2)2 = -1/2
Take square root of both sides:
x + 1/2 = √(-1/2)
And, sorry, but you're left with the square root of a negative number.
Have you learned about i, the "imaginary number" equal to the square root of negative 1? Because the right side of your equation is i over √2
This quadratic equation has no solutions because the discriminant is less than zero.
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
If you mean: 6x = 25+x then x = 5
This quadratic equation has no solutions because the discriminant is less than zero.
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
6x2 + 6x + 60 is an expression, not an equality nor inequality, and so there is nothing that can be solved. Also, the discriminant is negative and so the corresponding equation has no real solutions. All that can be said is:6x2 + 6x + 60 = 6(x2 + x + 10) = 6[(x + 1/2)2 - 1/4 + 10] = 6*[(x + 1/2)2 + 93/4].
16x+9 without the rest of the equation, what this equals, I can't solve
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
x2+6x-7 = 0 (x+3)2-7 = 0 (x+3)2-7-9 = 0 (x+3)2 = 16 x+3 = + or - 4 x = - 3 + or - 4 x = 1 or -7
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
If 6x + 10 = 11x , then x=2.
If you mean: 6x = 25+x then x = 5
-4x+3 = 23+6x -4x-6x = 23-3 -10x = 20 x = -2
You mean find vertex. Solving for X is another matter, using the quadratic formula here.Vertex form:X2 + 6X - 2 = 0X2 + 6X = 2Halve the linear term( 6), square it and add it to both sidesX2 + 6X + 9 = 2 + 9factor the left side and gather terms on the right(X + 3)2 = 11(X + 3)2 - 11 = 0================vertex form(- 3, - 11 )==========Vertex