You can't SOLVE something unless it's an EQUATION. So let's assume you mean the equation
6x² plus 6x plus 6 equals zero (a standard form for equations)
6x² + 6x + 6 = 0
same as
x² + x + 1 = 0 (div both sides by 6)
so
x² + x = -1
Now we can complete the square on THAT thing
x² + x + 1/2 = -1 + 1/2
(x + 1/2)2 = -1/2
Take square root of both sides:
x + 1/2 = √(-1/2)
And, sorry, but you're left with the square root of a negative number.
Have you learned about i, the "imaginary number" equal to the square root of negative 1? Because the right side of your equation is i over √2
This quadratic equation has no solutions because the discriminant is less than zero.
To solve the equation (x^2 + 6x - 18 = 0) by completing the square, first, move 18 to the other side: (x^2 + 6x = 18). Next, take half of the coefficient of (x) (which is 6), square it ((3^2 = 9)), and add it to both sides: (x^2 + 6x + 9 = 27). This can be factored as ((x + 3)^2 = 27). Taking the square root of both sides gives (x + 3 = \pm \sqrt{27}), leading to (x = -3 \pm 3\sqrt{3}).
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
This quadratic equation has no solutions because the discriminant is less than zero.
To solve the equation (x^2 + 6x - 18 = 0) by completing the square, first, move 18 to the other side: (x^2 + 6x = 18). Next, take half of the coefficient of (x) (which is 6), square it ((3^2 = 9)), and add it to both sides: (x^2 + 6x + 9 = 27). This can be factored as ((x + 3)^2 = 27). Taking the square root of both sides gives (x + 3 = \pm \sqrt{27}), leading to (x = -3 \pm 3\sqrt{3}).
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
6x2 + 6x + 60 is an expression, not an equality nor inequality, and so there is nothing that can be solved. Also, the discriminant is negative and so the corresponding equation has no real solutions. All that can be said is:6x2 + 6x + 60 = 6(x2 + x + 10) = 6[(x + 1/2)2 - 1/4 + 10] = 6*[(x + 1/2)2 + 93/4].
16x+9 without the rest of the equation, what this equals, I can't solve
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
x2+6x-7 = 0 (x+3)2-7 = 0 (x+3)2-7-9 = 0 (x+3)2 = 16 x+3 = + or - 4 x = - 3 + or - 4 x = 1 or -7
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
If 6x + 10 = 11x , then x=2.
If you mean: 6x = 25+x then x = 5
-4x+3 = 23+6x -4x-6x = 23-3 -10x = 20 x = -2