This quadratic equation has no solutions because the discriminant is less than zero.
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
This quadratic equation which will have two solutions can be solved by completing the square or by using the quadratic equation formula.Completing the square:x2+18x+4 = 0(x+9)2+4 = 0(x+9)2+4-81 = 0(x+9)2 = 77x+9 = + or - the square root of 77x = -9 + or - the square root of 77If you're not too sure about the procedure of completing the square your maths tutor should be familiar with it.
It cannot be solved because the discriminant of the quadratic equation is less than zero
24
This quadratic equation has no solutions because the discriminant is less than zero.
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
This quadratic equation which will have two solutions can be solved by completing the square or by using the quadratic equation formula.Completing the square:x2+18x+4 = 0(x+9)2+4 = 0(x+9)2+4-81 = 0(x+9)2 = 77x+9 = + or - the square root of 77x = -9 + or - the square root of 77If you're not too sure about the procedure of completing the square your maths tutor should be familiar with it.
It cannot be solved because the discriminant of the quadratic equation is less than zero
x = 2 or x = 2/5
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
The two solutions are the conjugate complex numbers, +i*sqrt(11) and -i*sqrt(11), where i is the imaginary square root of -1.
3x2+14x+8 = 0 x = -2/3 or x = -4
24
many solutions
There are 120 solutions.
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.