5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5
40
-1
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
4x - 7y = 12-7y = -4x + 12y = (4/7)x - (12/7)======================4x - 7y = 124x = 7y + 12x = (7/4)x + 3
4x to the 3rd power -4x to the 2nd power -43 when x=3
Is there an operator missing from this question? * 3 + 4x = 19 => x = 4 * 3 - 4x = 19 => x = -4 * 3 . 4x = 19 => x = 19/12
x + 5 = 4x/3 Solve for x multiply both sides of the equation by 3... 3 * (x + 5) = 3 * (4x/3) 3x + 15 = 4x subtract 3x from both sides of the equation (3x + 15) - 3x = (4x) - 3x 15 = x x = 15
8(4x+ 3)
5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5
40
-1
If the question gives 4x-3=9, then we can solve: 4x-3=9 4x=6 x=3/2, or 1.5
x= -.5
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
To solve 4x+3-x=4x-32 we use the additive property of equaility and add -3 to both sidesSo 4x-x=4x-32-3Simplify this by now subtracting 4x from both sides.-x=-35 or x=35Check it.3-35=-32 so it works.
4x - 7y = 12-7y = -4x + 12y = (4/7)x - (12/7)======================4x - 7y = 124x = 7y + 12x = (7/4)x + 3