-1
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x3 - 4x factor the common factor out
= x(x2 - 4) factor the difference of the squares
= x(x + 2)(x - 2)
If you want to find the values of x which make the given expression equal to zero, then it will happen if
x = 0, or
x + 2 = 0, which yields x = -2, or
x - 2 = 2; x = 2
5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5
40
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
-1
4x - 7y = 12-7y = -4x + 12y = (4/7)x - (12/7)======================4x - 7y = 124x = 7y + 12x = (7/4)x + 3