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well sir , you cant add anything to the fuel .

there are better types of fuel line now that are for flex fueled vehicles .

the small engine and marine industry got hit real bad with this problem as all there stuff was for gasoline not ethanol . look to find a after 2010 date code and a

"a-1 "rating from coast guard .also ther is a good article in popular hotrodding that can help if your auto parts store is clueless .

even some of the best s/s braded stuff wont last long in e-85

Q: How do you solve fuel line deterioration due to alcohol in 10 - 15 percent gasoline?

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That depends on what the question is. A percent is just a number. You're asking "How do you solve a number?"

166.6/100

A percent is simply a proportion out of 100.

70 * % = 14 Solve for percent and get 0.2, or 20%.

34.5%

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That depends on what the question is. A percent is just a number. You're asking "How do you solve a number?"

It tried to solve the use of alcohol. The 18th amendment banned the use of alcohol back then.

Alcohol and anti-depressants.

166.6/100

Alcohol and anti-depressants.

A percent is simply a proportion out of 100.

70 * % = 14 Solve for percent and get 0.2, or 20%.

you dont

Number*percent in a decimal 200 * .42 = 84

The total volume of solution equals 18 L. So if we let X be the 50% solution & Y be the 20% solution we can solve a set of two equations with 2 unknowns: X + Y = 18 (total volume of solution is 18 L) 0.5X + 0.2Y = 18*(0.30) (the total amount of alcohol in the new 18L solution) Solving simultaneously, multiply the 1st equation by 0.5 then substract to solve for Y. X + Y = 18 {*0.5} => 0.5X + 0.5Y = 9 0.5X + 0.2Y = 5.4 => 0.5X + 0.2Y = 5.4 ------------------------------------------------------- 0.3Y = 3.6 Y = 12 Then substitute for Y back into the 1st equation & solve to get X=6. So you need 12 L of the 20% solution & 6 L of the 50% solutions to mix together to get 18 L of a 30% alcohol solution.

U divide it by 100

34.5%