How do you solve quadratics using the principal square root function?

Answer 1

The first step is to write the quadratic in the form ax^2 + bx + c = 0 where x is the variable and a, b and c are constants.

Then the two solutions are

[- b - sqrt(b^2 - 4ac)]/(2a) and [- b + sqrt(b^2 - 4ac)]/(2a)

Answer 2

The details vary, depending on the "quadratic" you want to solve. For some equations, you can take the square root on both sides. Please note that doing this, some of the solutions can disappear in the modified equation (i.e., after taking the square root).