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You cannot.

It is not possible to solve one linear equation in two unknown variables; you need two independent equations.

Q: How do you solve this equatoin on graph y equals 2x-5?

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(2x5)-3

2x^3(x - 3)(x + 3)

lets say that you're doing a division problem that looks just like a multiplication problem. lets say its 10 divided by 5 so 2x5 equals 10 so the missing number in the problem is 2 MORE TO COME

It equals 60 Because 3•2 is 6 2•5 is 10 &. 10•6 is 60

you take the y=mx+b alright then you plug in your numbers. So say you got (5,4)(X,Y) and the slope was 2 the equation would then be 4=2(5)+b. Then you do 2x5 which equals 10. Then you divide the 10 on both sides. the 10 and the 10 cancel each other out and the 4/10 =2/5 and then 2/5=b. There you have it!

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First, remember the order of operations. 2x5 comes first. 2x5=10, which makes 11-10 which makes 1.

(2x5)-3

To find out what 5x equals to, you have to post the rest of the equation.

2x^3(x - 3)(x + 3)

10

2 x 5 is the prime factorization of 10.

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lets say that you're doing a division problem that looks just like a multiplication problem. lets say its 10 divided by 5 so 2x5 equals 10 so the missing number in the problem is 2 MORE TO COME

that's easy you do 2x5 and get 10x3 and get 30-4 and get 26

2 x 5 is the prime factorization of 10.

f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.

It equals 60 Because 3•2 is 6 2•5 is 10 &. 10•6 is 60