(2x5)-3
(3*5)+(6 to the power of 2)+54-5
3*6*2+5+5+54=100
4+3=5+2 or 4+5=32
You can get 5 using the numbers 2, 3, 4, and 5 by calculating (2^3 - 4 + 5). Here, (2^3) equals 8, and subtracting 4 gives you 4. Finally, adding 5 results in 5.
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
2+2+2+2+2-7 This is an equation that uses 5 2's yet equals 3.
(3*5)+(6 to the power of 2)+54-5
3*6*2+5+5+54=100
4+3=5+2 or 4+5=32
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
-2
Uhhh . . let me guess . . . 2+3 = 10 if you're using Base 5 math?
-2 plus 5 equals +3
trunc(79/35) = 2
2 + 3 + 5 + 7 = 17
The Commutative Property
5-2=3n=3