Make it a straightforward quadratic equation: 2x^2 - x - 36 = 0
Factorise: (2x - 9)(x + 4) = 0
If the whole expression equals 0, one of the bracketed terms must equal 0,
so x = 9/2 or -4
Check: 2 x 81/4 - 9/2 - 36 = 40½ - 4½ - 36. This equals 0;
2 x 16 -(-4) - 36 = 32 + 4 - 36. This also eqauls 0.
Given solution is therefore correct for both values of x.
2x+a=p 2x=p-a x=.5p-.5a
x = -8
X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0
2x - 8 = 10 2x = 10 + 8 2x = 18 x = 18 / 2 x = 9
-9-2x+x = -13 -2x+x = -13+9 -x = -4 x = 4
2x+a=p 2x=p-a x=.5p-.5a
x=12
x = -8
2x + 3 = x 2x + 3 - 3 = x - 3 2x = x - 3 2x - x = x - 3 - x x = -3
x-29 = 13+2x x-2x = 13+29 -x = 42 x = -42
meant to be e^x = 2e^1-2x
2x-3=9 so 2x=12 and x=6
To solve this equation we have to isolate and solve for x. So: 2x-6= x+5 +6 +6 2x = x+11 -x -x x = 11 So x=11.
X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0
2x - 8 = 10 2x = 10 + 8 2x = 18 x = 18 / 2 x = 9
-9-2x+x = -13 -2x+x = -13+9 -x = -4 x = 4
-530