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-2x + 1

Q: How do you write the sum of 1 and the quantity -2 times x?

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2 + (9*1) = 2 + 9 = 11

Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2

You can spell it out in words or write it as 99,999 + 1 or any equivalent sum, including 1+1+1+1... (a lakh times).

Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2

SUM = 0: FOR N = 1 to 100: SUM = SUM + N: Next N: PRINT CHR$(11); "Sum ="; SUM: END

Related questions

2 + (9*1) = 2 + 9 = 11

16x(1+a)

p-5/8(1/4+p)

n + 1

Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2

You can spell it out in words or write it as 99,999 + 1 or any equivalent sum, including 1+1+1+1... (a lakh times).

1

int i, sum; /* example using while */ sum = 0; i = 1; while (i <= 100) { sum += i; ++i; } /* example using for */ sum = 0; for (i = 1; i <= 100; ++i) sum += i;

Quantity x+4 times quantity x+1.

4x+x+18 = 14

Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2

SUM = 0: FOR N = 1 to 100: SUM = SUM + N: Next N: PRINT CHR$(11); "Sum ="; SUM: END