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Distance from (0, 0) to (5, 12) using distance formula is 13
In quadrant II, the x-value is negative and the y-value is positive. Since the point is 5 units from the origin, the x-coordinate will be -5. The point is also 4 units from the origin in the y-direction, making the y-coordinate 4. Therefore, the point is located at (-5, 4).
The origin, O is the point where the value on the number line is zero. Locate the a point 3 units to the left of the Origin, O and another point that is 5 units to the right of the origin. Join the two points with a straight line.
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If you mean the point of (2, 5) then the 1st step is to move 2 units to the right of the origin then move 5 units up to locate the given point.