7
Distance from (0, 0) to (5, 12) using distance formula is 13
In quadrant II, the x-value is negative and the y-value is positive. Since the point is 5 units from the origin, the x-coordinate will be -5. The point is also 4 units from the origin in the y-direction, making the y-coordinate 4. Therefore, the point is located at (-5, 4).
The origin, O is the point where the value on the number line is zero. Locate the a point 3 units to the left of the Origin, O and another point that is 5 units to the right of the origin. Join the two points with a straight line.
7.62
If you mean the point of (2, 5) then the 1st step is to move 2 units to the right of the origin then move 5 units up to locate the given point.
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Body of Proof - 2011 Point of Origin 2-5 is rated/received certificates of: Netherlands:12
Distance from (0, 0) to (5, 12) using distance formula is 13
13 good luck
ER - 1994 Point of Origin 5-18 was released on: USA: 8 April 1999
In quadrant II, the x-value is negative and the y-value is positive. Since the point is 5 units from the origin, the x-coordinate will be -5. The point is also 4 units from the origin in the y-direction, making the y-coordinate 4. Therefore, the point is located at (-5, 4).
The origin, O is the point where the value on the number line is zero. Locate the a point 3 units to the left of the Origin, O and another point that is 5 units to the right of the origin. Join the two points with a straight line.
13 miles
7.62
It is the point of origin which is located at (0, 0) on the Cartesian plane
If you mean the point of (2, 5) then the 1st step is to move 2 units to the right of the origin then move 5 units up to locate the given point.
Rotating it about the origin 180° (either way, it's half a turn) will transform a point with coordinates (x, y) to that with coordinates (-x, -y) Thus (2, 5) → (-2, -5)