The acceleration is expressed in meters per second square, which really means (meters / second) / second. Every second, the skydiver will be 10 meters per second faster than the previous second. Therefore, after 3 seconds, he will have a speed of 30 meters per second.
360
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
19.6 meters / 64.4 ft
Convert 78 mph to meters per second: 78 mph=35 meters/second The acceleration of earths gravity is 9.8 meters per second squared. This is constant. Therefore, using basic calculus, the velocity of a falling object is equal to 9.8 meters per second times the time it has fallen. 9.8*T=35 T=3.6 Thus, it takes roughly three and a half seconds for the average human body to accelerate to 78 miles per hour (assuming wind drag is inconsequential).
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
No
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
That depends what data you are given. Close to the Earth's surface, such an object will accelerate at 9.8 meters/second2, so if it starts from rest, after "n" seconds, it will have a speed of "9.8n" meters/second.
Less than 9.8 meters (32.2 feet) per second2.That would be his acceleration ... and also the acceleration of the feather falling next to him ... if there wereno air at all.
Upon leaving the aircraft, a skydiver rapidly reaches something called terminal velocity. This is where the resistance of the air matches the mass of the skydiver. At this speed, the skydiver maintains a relatively constant speed. Typically this is around 120mph in a flat body position and takes approximately 10 seconds to reach. For more questions about skydiving, see the attached link.
At any time after it starts falling, an object is falling 9.8 meters per second (32.2 feet per second) faster than it was falling one second earlier.
78.46 meters (257.4 feet)
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
9.8 meters/second2 x 10 seconds = 98 meters/second.
19.6 meters / 64.4 ft
98 meters (322 feet) per second.
Convert 78 mph to meters per second: 78 mph=35 meters/second The acceleration of earths gravity is 9.8 meters per second squared. This is constant. Therefore, using basic calculus, the velocity of a falling object is equal to 9.8 meters per second times the time it has fallen. 9.8*T=35 T=3.6 Thus, it takes roughly three and a half seconds for the average human body to accelerate to 78 miles per hour (assuming wind drag is inconsequential).