The acceleration is expressed in meters per second square, which really means (meters / second) / second. Every second, the skydiver will be 10 meters per second faster than the previous second. Therefore, after 3 seconds, he will have a speed of 30 meters per second.
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
19.6 meters / 64.4 ft
Convert 78 mph to meters per second: 78 mph=35 meters/second The acceleration of earths gravity is 9.8 meters per second squared. This is constant. Therefore, using basic calculus, the velocity of a falling object is equal to 9.8 meters per second times the time it has fallen. 9.8*T=35 T=3.6 Thus, it takes roughly three and a half seconds for the average human body to accelerate to 78 miles per hour (assuming wind drag is inconsequential).
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
That depends what data you are given. Close to the Earth's surface, such an object will accelerate at 9.8 meters/second2, so if it starts from rest, after "n" seconds, it will have a speed of "9.8n" meters/second.
The acceleration of the skydiver can be calculated using Newton's second law: F = ma, where F is the force of gravity - air resistance, m is the mass of the skydiver, and a is the acceleration. The acceleration will depend on the exact value of air resistance acting on the skydiver.
Upon leaving the aircraft, a skydiver rapidly reaches something called terminal velocity. This is where the resistance of the air matches the mass of the skydiver. At this speed, the skydiver maintains a relatively constant speed. Typically this is around 120mph in a flat body position and takes approximately 10 seconds to reach. For more questions about skydiving, see the attached link.
The acceleration due to gravity is 9.8 meters per second squared, not 98. This means that an object in free fall will increase its speed by 9.8 m/s every second.
19.6 meters / 64.4 ft
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
Convert 78 mph to meters per second: 78 mph=35 meters/second The acceleration of earths gravity is 9.8 meters per second squared. This is constant. Therefore, using basic calculus, the velocity of a falling object is equal to 9.8 meters per second times the time it has fallen. 9.8*T=35 T=3.6 Thus, it takes roughly three and a half seconds for the average human body to accelerate to 78 miles per hour (assuming wind drag is inconsequential).
The acceleration of gravity is 9.8 meters per second2 downward. 1.6 seconds after falling from a branch near the surface of the Earth, the apple's speed is 15.68 meters per second. It's velocity is 15.68 meters per second downward. The tree has to be really tall, since the apple falls 12.544 meters (about 41 feet) in 1.6 seconds.
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.