19.6 meters / 64.4 ft
a. 144 feet b. 96 ft/sec.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
89
240 ft
To find the change in height per second, we divide the total change in height by the total time taken. In this case, the change in height is 5000 feet and the total time is 200 seconds. Therefore, the change in height per second is 5000 feet / 200 seconds = 25 feet per second.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
The time it takes for a volleyball to hit the ground when dropped from a height depends on the height it falls from. Using the formula for free fall ( t = \sqrt{\frac{2h}{g}} ), where ( h ) is the height in meters and ( g ) is the acceleration due to gravity (approximately ( 9.81 , m/s^2 )), you can calculate the time. For example, if dropped from 2 meters, it would take about 0.64 seconds to hit the ground.
a. 144 feet b. 96 ft/sec.
Assuming the object is dropped from rest and neglecting air resistance, it would take approximately 7.0 seconds for the object to hit the ground from a height of 500 feet. This is based on the formula t = sqrt(2h/g), where t is the time, h is the height, and g is the acceleration due to gravity (approximately 32.2 ft/s^2).
Yes, two objects of the same mass dropped at different heights will have different speeds when they hit the ground due to the influence of gravity. The object dropped from a higher height will have a higher speed upon impact because it had more time to accelerate while falling.
The time it takes for a ball to hit the ground when dropped from a height can be calculated using the equation: t = √(2h/g), where h is the height (443 meters) and g is the acceleration due to gravity (9.81 m/s²). Solving for t gives a time of approximately 9 seconds.
An object dropped from a height without any initial velocity, a skydiver falling towards the ground before deploying their parachute, and a rock falling off a cliff are all examples of free fall.
Regardless of the height from which it is falling, (neglecting air resistance) it's speed will be 19.62 metres per second. (Acceleration from gravity is 9.81 metres per second squared, so after 1 second it is moving at 9.81 metres per second and after 2 seconds it is moving at 19.62 metres per second.
Terminal velocity is typically reached within 10-12 seconds when falling from a height, depending on factors such as air resistance and the height of the fall.
A rock that is dropped, and a apple falling from a tree.Hold a ball in your hand, stretch out your arm, and drop the ball. As it is moving towards the ground, it is in free fall.
When an object is dropped from a certain height, the time it takes to reach the ground is independent of the height (assuming no air resistance). Therefore, whether you drop the object from three times the initial height or the original height, it will still take the same time (T) to reach the ground.
All objects dropped from the same height will hit the ground at the same time, regardless of their mass or shape, as long as air resistance is negligible. Thus, the marble, textbook, and flaming stick will hit the ground simultaneously.