30 m/s
Use the kinematic equation: vf = vi + at,
where:
vf is final velocity (?), vi is initial velocity (0 m/s), a is acceleration (6 m/s2), and t is time (5 s).
Plug the known values into the equation and solve.
vf = 0 + (6 m/s21)(5 s) = (6 m/s)(5) = 30 m/s
The speed, in this case, is the acceleration multiplied by the time.
Acceleration is not measured in metres per second but in metres per second-squared. Assuming the latter, the car will be going at 30 metres per second.
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
-2.33 metres per second squared
Acceleration is measured in m/s2 (metres per second squared)
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
It is not possible to answer this question without the starting velocity.
60.912 meters in that time
That's easy, if the car is initially traveling at 25 meters per second and gradually accelerates 3 meters per second for 6 seconds then the car is traveling at 43 meters per second.
gravity
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
The answer is B - 3 meters per second squared
The acceleration of the body is 3 m/sΒ²
3 m/s2
The acceleration due to gravity alone on Earth is about 9.81 meters per second-squared.
5 metres per second squared
-2.33 metres per second squared
1.667 metres per second squared
Acceleration is measured in m/s2 (metres per second squared)