30 m/s
Use the kinematic equation: vf = vi + at,
where:
vf is final velocity (?), vi is initial velocity (0 m/s), a is acceleration (6 m/s2), and t is time (5 s).
Plug the known values into the equation and solve.
vf = 0 + (6 m/s21)(5 s) = (6 m/s)(5) = 30 m/s
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
An object in free fall accelerates due to gravity at approximately 9.81 meters per second squared. After two seconds, its velocity can be calculated using the formula ( v = g \cdot t ), where ( g ) is the acceleration due to gravity. Thus, after two seconds, the object would be falling at about ( 19.62 ) meters per second (m/s) downward.
-2.33 metres per second squared
Acceleration is measured in m/s2 (metres per second squared)
It is not possible to answer this question without the starting velocity.
60.912 meters in that time
That's easy, if the car is initially traveling at 25 meters per second and gradually accelerates 3 meters per second for 6 seconds then the car is traveling at 43 meters per second.
gravity
To convert 4.4 miles per hour per second to meters per second squared, first convert 4.4 miles to meters (1 mile = 1609.34 meters) and 1 hour to seconds (1 hour = 3600 seconds). Then divide the speed in meters per second by the time in seconds squared to get the acceleration in meters per second squared.
6 meters per second. Explanation: After 1 second = 2 meters per second. After 2 seconds = 4 meters per second. After 3 seconds = 6 meters per second.
The answer is B - 3 meters per second squared
3 m/s2
The acceleration of the body is 3 m/s²
5 metres per second squared
Seconds are not squared in the acceleration formula. The units for acceleration are meters per second squared (m/s^2), where the time unit (seconds) is squared to represent the change in velocity over time.
-2.33 metres per second squared
1.667 metres per second squared