70
You cannot set a ladder 60 degrees above the ground
I believe that you're asking how high up the side of a building could a ladder reach if it was leaning against a building with the base of the ladder making a 60 degree internal angle from the ground.
If that's the case, you answer is 8.66 ft. Using trigonometric principles for right triangles, we know the hypotenuse (10 ft) and two* of the angles in the triangle (the 60 degrees between the ladder and the ground, and the 90 degrees between the ground and the building). From there, we can use the sine function (SIN on the calculator) to get ratio. Then, we would multiply the ratio by the hypotenuse to get our answer.
Here, we'd enter 60 into our calculator and hit the SIN button to get .866 (rounded). Then we just multiply by 10, and get our answer of 8.66 (rounded).
*Technically, if we know two angles in a triangle, we know all three because all angles in right triangles always add up to 180 degrees. So if you wanted to check yourself, you could use the 'unknown' angle and use the cosine function (COS), then multiply by the hypotenuse to verify.
Using Pythagoras' theorem the the foot of the ladder should be 12 feet away from the base of the building.
20
12 feet.
Use Pythagoras' theorem: 152-92 = 144 and the square root of 144 is 12 Answer: 12 feet
The leg opposite the 58 degree angle is the height of the kite above the ground. So, the leg is 36 ft.
The ladder forms a right angle with the building: the ground and the building forming the right angle and the ladder forming the hypotenuse. If the length of the ladder is L metres, then sin(49) = 12/L So L = 12/sin(49) = 15.9 = 16 metres.
This answer uses trigonometry to avoid a lot of work:tangent = opposite/adjacent and tangent*adjacent (base of ladder from the building) = opposite (height of ladder above ground)So: tangent 60 degrees*3 = 5.196152423Therefore: Top of the ladder above ground = 5.2 meters correct to one decimal place.More laborious methodThe right triangle formed by the wall, ground and ladder has sides in the ratio of 1::2::sq-rt-of-3. The shortest side is the one opposite the 30 degree angle, i.e., the given distance from wall to base of the ladder--3 m.The length of the ladder represents the hypotenuse of the triangle, and is twice as long, hence 6 m.And the height of the ladder's top from the ground is proportional to the third side whose length is sq-rt-3 times that of the shortest side. Sq-rt-3 is about 1.732, so height of the ladder's top at the wall is about 5.20 m, or 520 cm.
17
If it is an above ground yes
Using Pythagoras' theorem the the foot of the ladder should be 12 feet away from the base of the building.
Ladder's are very important in a swimming pool. If you don't have a ladder, people can get hurt. If there is an emergency and someone needs help, it would take a while for the person to get help.
20
12 feet
Using Pythagoras' theorem the length of the base is 7 feet
9
12
12 feet.