The perimeter is: 1+10+1+10 = 22 cm
Let the length of the short stick be s cm; then: The longer stick is s + 22 cm. And the two sticks together is: s cm + (s + 22) cm = 142 cm → 2s + 22 cm = 142 cm This can then be solved for s, the length of the shorter stick; from which the longer stick length can be found.
11 in is greater then 22 cm. 11 inches is 27.94 cm. 22 cm is 8.66142 inches
That means the bone is 28 1/2 cm long. 10 mm in a cm. 285 mm
Perimeter = 4*22 = 88 cm
from 2 to 22 cm long.
The perimeter is: 1+10+1+10 = 22 cm
Let the length of the short stick be s cm; then: The longer stick is s + 22 cm. And the two sticks together is: s cm + (s + 22) cm = 142 cm → 2s + 22 cm = 142 cm This can then be solved for s, the length of the shorter stick; from which the longer stick length can be found.
There need not be any force.
The ball is about 11 inches (28 cm) long and about 22 inches (56 cm) in circumference at the center.
The ball is about 11 inches (28 cm) long and about 22 inches (56 cm) in circumference at the center.
11 in is greater then 22 cm. 11 inches is 27.94 cm. 22 cm is 8.66142 inches
22/1 cm40% of 55 cm= 40% * 55 cm= 0.40 * 55 cm= 22 cm= 22/1 cm
(1 + 10) × 2 = 22 cmNote: there are ten mm to 1 cm.So 10 mm is 1 cm
22 cm. 2 dm=20 cm 22 cm-20 cm=2 cm
22
22 dam = 220 m = 22 000 cm