Find the surface area of the pyramid
15 m 12m
The perimeter is: 1+10+1+10 = 22 cm
Let the length of the short stick be s cm; then: The longer stick is s + 22 cm. And the two sticks together is: s cm + (s + 22) cm = 142 cm → 2s + 22 cm = 142 cm This can then be solved for s, the length of the shorter stick; from which the longer stick length can be found.
11 in is greater then 22 cm. 11 inches is 27.94 cm. 22 cm is 8.66142 inches
That means the bone is 28 1/2 cm long. 10 mm in a cm. 285 mm
Perimeter = 4*22 = 88 cm
from 2 to 22 cm long.
The perimeter is: 1+10+1+10 = 22 cm
if something measures from the 22 cm mark to the 50 cm mark the lenghth is
Let the length of the short stick be s cm; then: The longer stick is s + 22 cm. And the two sticks together is: s cm + (s + 22) cm = 142 cm → 2s + 22 cm = 142 cm This can then be solved for s, the length of the shorter stick; from which the longer stick length can be found.
There need not be any force.
The ball is about 11 inches (28 cm) long and about 22 inches (56 cm) in circumference at the center.
The ball is about 11 inches (28 cm) long and about 22 inches (56 cm) in circumference at the center.
11 in is greater then 22 cm. 11 inches is 27.94 cm. 22 cm is 8.66142 inches
22/1 cm40% of 55 cm= 40% * 55 cm= 0.40 * 55 cm= 22 cm= 22/1 cm
(1 + 10) × 2 = 22 cmNote: there are ten mm to 1 cm.So 10 mm is 1 cm
22 cm. 2 dm=20 cm 22 cm-20 cm=2 cm
22 x 22 = 484 sq cm or cm2