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First of all, it depends on how fast it was falling at the start of its fall. Also, it depends on the air resistance. Since you did not give any, let's say that air resistance is 0 and the velocity of the object when it started its fall is 0 Since the formula is d=v(0)*t+(1/2)9.8*t^2 d=(1/2)9.8*t^2 since the start speed was 0 (v(0) is starting speed) d = 4.9*t^2 replace D with what we know. 30,000 feet is 9,144 meters. So - t*t=9144/4.9 So the square of T =1866.122449 (rounded it) T = is the square root of 1866.122449 Finally, T = 43.198639 T is about 43.2 seconds So, it would take about 43.2 seconds

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16y ago

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Anonymous

4y ago
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Q: How long will it take an object to fall 30000 feet?
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