Well, honey, to change ice at 20 degrees F to steam at 220 degrees F, you'd need to go through a whole rollercoaster of phase changes. It takes 144 BTUs to melt one pound of ice, and 970 BTUs to turn one pound of water into steam. So, for five pounds of ice, you're looking at a total of 7,070 BTUs to go from ice to steam. Hope that helps, sugar!
80 lbs until past 45 degrees
BTUs, or British Thermal Units, measure the amount of heat energy required to raise the temperature of one pound of water by one degree Fahrenheit. The formula to calculate BTUs is: BTUs = weight of water (in pounds) x temperature change (in degrees Fahrenheit) x 1. Alternatively, the formula can be expressed as: BTUs = (Flow rate in gallons per minute x change in temperature in degrees Fahrenheit) / 500.
Formula: pounds x 0.453 = kg
The amount of money in a change jar that weighs fifteen pounds would depend on the denominations of the coins. For U.S. coins, a general estimate is that 1 pound of mixed change is approximately $20-$25. Therefore, with 15 pounds, the change jar could contain anywhere from $300 to $375.
The factor is 0.454
6,520 Btus
1.5million
To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
To calculate the heat energy required to change the temperature of a substance, you can use the formula: Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Given that steam has a specific heat capacity of approximately 0.5 btu/lb°F, you can calculate the required heat energy by plugging in the values: Q = 10 lb * 0.5 btu/lb°F * (240°F - 212°F).
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200
The amount of energy that is required to 160 cfm of air from 10 to 170 degrees F is 200 btu. T he formula is weight x specific heat x temperature difference so we have10 pounds x 1.00 x 2010 for 10 pounds of water.
To calculate the heat required to cool steam to water at a lower temperature, you can use the formula: Q = mcΔT Where: Q = heat energy m = mass c = specific heat capacity ΔT = change in temperature Given: m = 5 pounds ΔT = (232 - 162) = 70 degrees F Specific heat capacity of water = 1 cal/g°C Convert pounds to grams: 1 pound ≈ 453.592 grams Now, plug in the values into the formula to calculate the heat energy.
At 32 degrees, just before it freezes . . . 62.42 pounds At 120 degrees, roughly midway between freezing and boiling . . . . 61.71 pounds At 180 degrees ... really really really hot . . . 60.58 pounds At 212 degrees, just before it boils . . . 59.83 pounds
20 LBS OF PROPANE WILL PRODUCE APPROX. 36,000 BTU @ 0 DEGRESS, 51,000 @ 20 DEGREES.