The question cannot be answered because:
6519.2 btus are required.
how can solve this question .
6,520 Btu/h
1304
6520
6,520Btu
13,040
80 lbs until past 45 degrees
Brakes.
Formula: pounds x 0.453 = kg
140 pounds = 63,500 grams.Formula: pounds x 453.6 = grams
The factor is 0.454
6,520 Btus
1.5million
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200
The amount of energy that is required to 160 cfm of air from 10 to 170 degrees F is 200 btu. T he formula is weight x specific heat x temperature difference so we have10 pounds x 1.00 x 2010 for 10 pounds of water.
How many degrees water weights 7975 pounds
20 LBS OF PROPANE WILL PRODUCE APPROX. 36,000 BTU @ 0 DEGRESS, 51,000 @ 20 DEGREES.
At 32 degrees, just before it freezes . . . 62.42 pounds At 120 degrees, roughly midway between freezing and boiling . . . . 61.71 pounds At 180 degrees ... really really really hot . . . 60.58 pounds At 212 degrees, just before it boils . . . 59.83 pounds
80 lbs until past 45 degrees
4.2 pounds at 60 degrees F. 4.2 pounds at 60 degrees F.
There is no relationship between degrees(which is an angle or temperarure) and pounds which is a weight or currrency) . They are two totally different things)
12 x sin 60 = 11.08 pounds