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one square yard would take 9 blocks

and one cubic yard would take 27 blocks,

that is if the question is written correctly

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Q: How many blocks that are 1 foot long on each edge would be needed to fill a cubical box with edges 1 yard long?

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the sides of the cubical box would be 7 meters

253.125 blocks.

When you say 1 foot block, are they square blocks with side equal to 1 foot, in that case you would need 240 blocks

I believe it would have nine edges.

There are nine edges.

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9 cause the volume is 9

1 ft = 12 in → question is how many inch cubes fit in a 12 in by 12 in by 12 in cube. 12 small blocks fit across the front of the box in a row 12 rows of these 12 small blocks fit back from the back in a layer of blocks 12 layers of these blocks fit in the box Thus you will need 12 × 12 × 12 = 1,728 blocks.

the sides of the cubical box would be 7 meters

253.125 blocks.

96 g

210

The coefficient of cubical expansivity would normally be the cube of the coefficient of linear expansivity unless that coefficient is different in different directions for a material. In that case it would be the product of the linear coefficients in the different directions.

When you say 1 foot block, are they square blocks with side equal to 1 foot, in that case you would need 240 blocks

The modifications needed to make a 1982 'vette as fast as an Enzo would go beyond a couple of 'blocks', unfortunately.

The only information you've given is that there is a surface with an area of 50,000 ft2. We need to know the size of the blocks to know how many are going to fit. If we assume for the blocks length L and width W, then all we can do for now is assume this formula: 50,000 ft2/L*W = number of the blocks needed

Yes. All prisms have edges. Edges are defined as where two faces meet. The base of the prism would have 6 edges since the base would be a hexagon. The second base (or the top) would also have 6 edges since it would have to be another hexagon. lastly, there would be 6 edges connecting the 6 vertices of the bases for a total of 18 edges.

A point would have neither edges or vertices