412000
6 cm tall
7
7.5 cm
Since there are zero cubes in the stack, the surface area is zero sq cm.
The value of the stack would depend on how worn the dimes are. If you accept that a US dime is between 1.35 and 1.40 mm thick, then the value of the stack would worth between $264.30 and $274.00. 37cm * 10 mm per cm / 1.35mm = 2740074074074074 ~ $274.00 37cm * 10 mm per cm / 1.40mm = 264.285714285714 ~ $264.30
A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).
412000
6 cm tall
7
about 10cm because 1 dime=1mm* * * * *That would be OK if a dime was 1 mm but it isn't. It is 1.35 mm so that a stack of 100 is 135 mm = 13.5 cm.
15870
10 cm or 100 mm.
7.5 cm
Since there are zero cubes in the stack, the surface area is zero sq cm.
500
To determine the height of a stack of 13 steel shims given a rectangular shape with a thickness of 1.27 cm, we need to calculate the total height by multiplying the thickness by the number of shims in the stack. Height of one shim = 1.27 cm Number of shims = 13 Total height = Height of one shim * Number of shims = 1.27 cm * 13 = 16.51 cm Therefore, the height of a stack of 13 steel shims, each with a rectangular shape of 1.27 cm thickness, is 16.51 cm.