412000
6 cm tall
7
7.5 cm
500
The value of the stack would depend on how worn the dimes are. If you accept that a US dime is between 1.35 and 1.40 mm thick, then the value of the stack would worth between $264.30 and $274.00. 37cm * 10 mm per cm / 1.35mm = 2740074074074074 ~ $274.00 37cm * 10 mm per cm / 1.40mm = 264.285714285714 ~ $264.30
A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).A dime is 1.35 mm (0.135 cm) thick so a 5 cm stack would contain5/0.135 = 37.04 coins (approx).
412000
6 cm tall
7
about 10cm because 1 dime=1mm* * * * *That would be OK if a dime was 1 mm but it isn't. It is 1.35 mm so that a stack of 100 is 135 mm = 13.5 cm.
15870
10 cm or 100 mm.
7.5 cm
To find the surface area of a single cube, you calculate the area of each face (6 faces) and add them together. Each face has an area of 1 cm x 1 cm = 1 cm². Therefore, the surface area of one cube is 6 cm². If the stack consists of n cubes, the total surface area would be 6n cm².
500
To determine the height of a stack of 13 steel shims given a rectangular shape with a thickness of 1.27 cm, we need to calculate the total height by multiplying the thickness by the number of shims in the stack. Height of one shim = 1.27 cm Number of shims = 13 Total height = Height of one shim * Number of shims = 1.27 cm * 13 = 16.51 cm Therefore, the height of a stack of 13 steel shims, each with a rectangular shape of 1.27 cm thickness, is 16.51 cm.