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Q: How many possible remainders if the divisor is 7?

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8 integer remainders. From 0 to 7 (inclusive).

The possible number of remainders is always one less than the divisor.

The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.

With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.

There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.

There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.

All non-negative numbers smaller than 9 ie 0, 1, 2, 3, 4, 5, 6, 7 and 8.

Any non-negative number smaller than 7.

7

Assuming you are dividing an integer... Eleven - the remainder can be: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10.

456y67783

31.(714285 repeating) or if your teacher accepts remainders: 7 R5.

4

One less than the divisor, so 6.

No.

7

No

No.

No

The answer depends on A.

for a integer n, we call d the divisor of n if d divides n without leaving a remainder. So, for example, 49/7=7 and 7 is a divisor or a factor of 49. ( n=49, d=7 in this case) Since 7 is the divisor the reciprocal of 7 is just 1/7. In general is n is a divisor, 1/n is the reciprocal.

It is called the multiplier.

The Greatest Common Divisor (GCD) for 7 4 is 1.

The divisor is 6 and the quotient is 7 because 42/6 = 7

For example: 35/7 35 is the dividend and 7 is the divisor 35 divided by 7 equals a quotient of 5

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