If the dividend is a multiple of 8 then there will be no remainders in the quotient otherwise the possible remainders are limitless
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.
There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.
There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.
If the dividend is a multiple of 8 then there will be no remainders in the quotient otherwise the possible remainders are limitless
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.
There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.
There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.
Walang remainder
The possible number of remainders is always one less than the divisor.
There are 8 possible remainders - including 0.
Anything less than 8.
Assuming you are dividing an integer... Eleven - the remainder can be: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10.
Both 16 and 8 are divisors of 64, since both can divide 64 without any remainders. 64/16=4 and 64/8=8.
All non-negative numbers smaller than 9 ie 0, 1, 2, 3, 4, 5, 6, 7 and 8.