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Q: How many possible remainders will you have if your divisor is 9?

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There are 10 possible divisors, the numbers 0 to 9.

There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.

All non-negative numbers smaller than 9 ie 0, 1, 2, 3, 4, 5, 6, 7 and 8.

8 is the greatest possible whole number remainder, eg seventeen divided by nine...

The divisor is 9. quotient x divisor + remainder = dividend ⇒ quotient x divisor = dividend - remainder ⇒ divisor = (dividend - remainder) ÷ quotient = (53 - 8) ÷ 5 = 45 ÷ 5 = 9

Related questions

There are 10 possible divisors, the numbers 0 to 9.

There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.

All non-negative numbers smaller than 9 ie 0, 1, 2, 3, 4, 5, 6, 7 and 8.

It will probably depend on the dividend (the number to be divided)

It depends on the dividend.

Assuming you are dividing an integer... Eleven - the remainder can be: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10.

9 times with no remainder

Exactly 5 times with no remainder

5 times, remainder 6

71 times with a remainder of 1

9.5556

Any non-negative integer less than the number that you are dividing by.

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