If the interior angle of a regular polygon is an integer, then so is the exterior angle.
For a regular polygon, the exterior angles are all the same and can be calculated as 360° ÷ number of sides; for this to be an integer, the number of sides must be a factor of 360.
To be a polygon, the shape must have at least 3 sides
So the question is the same as how many factors are there of 360 which are greater than or equal to 3.
360 = 2³ × 3² × 5 → it has (3+1)×(2+1)×(1+1) = 4×3×2 = 24 factors
Of these, the factors 1 (= 2⁰ × 3⁰ × 5⁰) and 2 (= 2¹ × 3⁰ × 5⁰) are less than 3, so there are 24 - 2 = 22 factors greater than or equal to 3.
→ there are 22 regular polygons with integer interior angles.
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The factors of 360 are: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, 180, 360
→The regular polygons with integer interior angles are:
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Regular polygons are those polygons that are bothequilateral (all sides congruent) and equilateral (all interior angles congruent).
All regular polygons have equal lengths and equal interior angles but irregular polygons have variations in sizes.
Yes in general polygons that have equal interior angles also have equal sides and they are said to be regular polygons. But a rectangle is an exception.
Interior Angles: n-2 (n is number of sides) ____ 180 Exterior angles are always 360 degrees.
The tessellating polygons must meet at a point. At that point, the sum of the interior angles of the polygons must 360 degrees - the sum of angles around any point. Therefore, each interior angle must divide 360 evenly. There is no 1 or 2 sided polygon. The interior angle of a regular pentagon is 108 degrees which does not divide 360 degrees. The interior angles of regular polygons with 7 or more sides lie in the range (120, 180) degrees and so cannot divide 360.That leaves regular polygons with 3, 4 or 6 sides.