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x^2 + 14x + 40 factorises as (x + 10)(x + 4) so the roots are x = -10, -4.
If: 14x = 56Then x = 56/14Therefore: x = 4
10 + 14x - 3 is pretty much the same thing as 7 + 14x. You can't solve this problem without knowing what x is or what the equation equals out to. For example, if 10 + 14x - 3 = 21, x would equal 1.
Equations: 7x+4y = 9 and 2x+3y = 1 Multiply all terms in the 1st equation by 2 and all terms in the 2nd equation by 7 So: 14x+8y = 18 and 14x+21y = 7 Subtract the 1st equation from the 2nd equation: 13y = -11 => y = -11/13 By substituting y = -11/13 into any of the equations x = 23/13 Therefore the solutions are: x = 23/13 and y = -11/13
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (-7 plus or minus the square root of 91) divided by 2 x = 1.269696 x = -8.269696
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That looks like a linear equation (no quadratic or higher terms), so you can expect it to have a single solution. However, actually solving the equation is not difficult; do it, to confirm this.
x^2 + 14x + 40 factorises as (x + 10)(x + 4) so the roots are x = -10, -4.
14x = 5 x = 5/14
It is an equation and the value of x is -9.25
Since y=14x is a perfect linear relation, the correlation would be 1.
6x-14x+16=27+11 answer: 4
If you mean: y = 14x+2 then the slope is 14 and the y intercept is 2
If: 14x = 56Then x = 56/14Therefore: x = 4
10 + 14x - 3 is pretty much the same thing as 7 + 14x. You can't solve this problem without knowing what x is or what the equation equals out to. For example, if 10 + 14x - 3 = 21, x would equal 1.
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
Equations: 7x+4y = 9 and 2x+3y = 1 Multiply all terms in the 1st equation by 2 and all terms in the 2nd equation by 7 So: 14x+8y = 18 and 14x+21y = 7 Subtract the 1st equation from the 2nd equation: 13y = -11 => y = -11/13 By substituting y = -11/13 into any of the equations x = 23/13 Therefore the solutions are: x = 23/13 and y = -11/13