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What will be the first term and the common ratio of geometric progression whose 6th and 9th terms are 160 and 1280 respectively?
Wiki User
ā 10y ago
ar5 = 160
ar8 = 1280
so r3 = 1280/160 = 8 and so r = 2
then, ar5 = 160 gives a = 160/32 = 5
First term = a = 5
Common ratio = r = 2
Wiki User
ā 10y ago
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What is the sum of the first 15 terms of an arithmetic?
For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
What is the formula for the geometric progression with the first 3 terms 4 2 1?
The nth term of the series is [ 4/2(n-1) ].
What does Geometric Series represent?
A geometric series represents the partial sums of a geometric sequence. The nth term in a geometric series with first term a and common ratio r is:T(n) = a(1 - r^n)/(1 - r)
What is the 7th term in the geometric sequence whose first term is 5 and the common ratio is -2?
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
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11.27357
What is the sum of the first 15 terms of an arithmetic?
For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
How do you find the ratio in the geometric progression?
Divide any term, except the first, by the term before it.
What is the difference between arithmetic progression and geometric progression?
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
The first and fourth terms of a geometric progression are 54 and 2 respectively Find the sum to infinity of the geometric progression?
t(1) = a = 54 t(4) = a*r^3 = 2 t(4)/t(1) = r^3 = 2/54 = 1/27 and so r = 1/3 Then sum to infinity = a/(1 - r) = 54/(1 - 1/3) = 54/(2/3) = 81.
A geometric progression has a common ratio -1/2 and the sum of its first 3 terms is 18. Find the sum to infinity?
The sum to infinity of a geometric series is given by the formula Sā=a1/(1-r), where a1 is the first term in the series and r is found by dividing any term by the term immediately before it.
What is the formula for the geometric progression with the first 3 terms 4 2 1?
The nth term of the series is [ 4/2(n-1) ].
What is the difference of arithmetic progression to geometric progression?
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant.That is,Arithmetic progressionU(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1) + d = U(1) + (n-1)*dGeometric progressionU(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1)*r = U(1)*r^(n-1).
What does Geometric Series represent?
A geometric series represents the partial sums of a geometric sequence. The nth term in a geometric series with first term a and common ratio r is:T(n) = a(1 - r^n)/(1 - r)
What is the 7th term in the geometric sequence whose first term is 5 and the common ratio is -2?
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
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It appears to have been Svante Arrhenius (1859-1927) in 1896, a Swedish scientist who developed what is now know as the 'greenhouse gas law':"if the quantity of carbonic acid increases in geometric progression, the augmentation of the temperature will increase nearly in arithmetic progression"
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11.27357
What is the 12th term in a geometric sequence that has a first term of 6 and a common ratio of 3?
It is 1062882.
