0 or 1 times depending on whether the signs between the x and y terms in the two equations are the same or different. Thanks to the Answer.com browser, we cannot see them!
0 or 1 times depending on whether the signs between the x and y terms in the two equations are the same or different. Thanks to the Answer.com browser, we cannot see them!
0 or 1 times depending on whether the signs between the x and y terms in the two equations are the same or different. Thanks to the Answer.com browser, we cannot see them!
0 or 1 times depending on whether the signs between the x and y terms in the two equations are the same or different. Thanks to the Answer.com browser, we cannot see them!
y = 2x2 + 3 does not intersect the x-axis at all. It has two imaginary roots at ±i * square root of 3/2.
At the point (2, 4).
They don't. The line is parallel. ( 4x-8x=12 simplifies to y-2x+3, which has the same slope as y=2x+2)
x = 3 and y = 4 so the lines intersect at (3, 4)
14x3
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y = 2x2 + 3 does not intersect the x-axis at all. It has two imaginary roots at ±i * square root of 3/2.
x = 3 and y = 2 (3,2)
At the point (2, 4).
None. When these two equations are graphed, the two lines are parallel. Since they never intersect, there is no point that satisfies both equations.
2x * 2x (2*2=4) therefore, 2x*2x equals 4x2.
No, x + x equals 2x. x times x equals x2. (x times x equals x squared.)
They don't. The line is parallel. ( 4x-8x=12 simplifies to y-2x+3, which has the same slope as y=2x+2)
x = 3 and y = 4 so the lines intersect at (3, 4)
14x3
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.
y=(2x)2 y=2(2x) y=4x