There is a possible confusion over how the last part of your question ("contain no 5") can be interpreted:
In interpretation number 1 there are no such numbers, as 5 is less than 10 and all two digit numbers are greater than, or equal to 10 (I suspect that this meaning is definitely not intended).
There are 90 two digit numbers (10 - 99); of them:
9 contain a 5 as the second digit: 15, 25, ..., 95
10 contain a 5 as the first digit: 50, 51, ..., 59
So there are 19 of the digit 5 used.
However, 55 is counted twice, meaning there are 18 numbers which contain the digit 5. (This is the solution to the interpretation number 2.)
Which means there are 90 - 18 = 72 numbers which do not contain the digit 5. (The solution to interpretation number 3, which I suspect is the required answer.)
Use whichever solution meets your intended interpretation of the question you wrote.
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04,14,24,34,40,41,42,43,44,45,46,47,48,49,54,64,74,84,94.... OR 19 Digits
There is only one such number.
There is no THE two-digit natural number because there are many of them. 10, 11, 12, .. 99 are all 2-digit natural numbers.
You see how many times the two digit number goes into the first two numbers then you will take them away and then you will get the third number and put it on the end of your answer then you will see how many times your two digit number goes into your new number and then you will get your answer. And by the way I am eleven and I am still in primary school so you should really know it. I can divide a two digit by a seventeen digit number and that ins easy peasy.
Highest 2-digit number = 99Highest 1-digit number = 999 - 9 = 90 two-digit numbers90.