bb
Music notes are indeed named after the first few letters of the alphabet. The note names of music notes cover the alphabet from A to G.
The nitrogen bases of DNA have letters A, C, G, T to represent it. B is absent in DNA
E C# B A B C# B A E C#Hope that helps! :)
keys
All I can see is that there are about 144 ways you can arrange these letters. So ya it'll probably take a while to figure this question out.
First, count how many letters you have--A, B, C, D, E, and F--6. Then, the problem is the number multiplied by the ones below it. 6x5x4x3x2x1. You can get rid of the one, because anything multiplied by 1 is itself. 6x5x4x3x2=720. You can arrange these six letters in 720 possible ways. If the row could be vertical or horizontal, the number doubles to 1440.
If the four letters "A" are to be together, "AAAA", then it's like having four differentletters; AAAA, L, B, M.The number of different arrangements (permutations) of the 7 letters in the word"ALABAMA" putting the four As together are;4! =4x3x2x1 =24
Tribal
r b l j a y c e a
There are 6! = 6*5*4*3*2*1 = 720 ways.In half of these b will be to the left of e and in the other half it will be to the right. So the answer is 360 ways.
The letters A B O U T can be arranged 120 different ways. This is the number of permutations of 5 things taken 5 at a time, or 5 factorial.
There are 11 letters. But 2 letters repeat; the i and b. The i occurs 2 times, as does the b. Therefore, the total number of ways to arrange PROBABILITY is 11!/(2!2!)=9,979,200 ways [I'm not the user who wrote this answer, but I am one "editing" it and writing this in the "[,]" things. But really, I just have a question. Can you say "11!/(2!2!)=9,979,200 ways" in a simpler way because I don't understand it (I am not an adult :) ). Please change this answer soon!]
Boomer?
There are 11 factorial, or 39,916,800 permutations of the letters in the word PROBABILITY. However, because the letters B and I are duplicated, there are only one quarter of that, or 9,979,200 distinguishable permutations.
1. B g p y2. G p y b3. P y b g4. Y b g p
Only 5 ways: one each with one of the letters missing.