There are 11 letters. But 2 letters repeat; the i and b.
The i occurs 2 times, as does the b.
Therefore, the total number of ways to arrange PROBABILITY is 11!/(2!2!)=9,979,200 ways
[I'm not the user who wrote this answer, but I am one "editing" it and writing this in the "[,]" things. But really, I just have a question. Can you say "11!/(2!2!)=9,979,200 ways" in a simpler way because I don't understand it (I am not an adult :) ). Please change this answer soon!]
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نقسم عدد الحروف فكتوريال على عدد ال وجود كل حرف بالكلمه فكتوريال حيصير 11 فكتوريال على 2 في 2 فكتوريال لان حرف b ,i متكررات مرتين
how many ways can 8 letters be arranged
4! = 24, they can be arranged in 24 different ways
They can't be arranged in a million different ways!
There are 1,663,200 ways.
There are 45360 ways.