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40 chickens and 30 pigs
This can be solved with 2 equations. Let p = the number of pigs and c = the number of chickens. Pigs and chickens each have 1 head, so p+c=70. Pigs have 4 legs and chickens have 2, so the total number of legs is 4p+2c=200.
Solve this "system of equations" by substitution: The first equation can be written as p=70-c. Substitute the right side for p in the second equation:
4(70 - c) + 2c = 200
280 - 4c + 2c = 200
280 - 2c = 200
-2c = 200 - 280
-2c = -80
c = 40.
Substitute this back into p=70-c: p=70-40=30.
There are 40 chickens and 30 pigs.
Check (in the words of the question): 40 chicken heads and 30 pig heads = 70 heads. 40x2=80 chicken legs, and 30x4=120 pig legs; 80+120=200 legs. Check!
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26
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How many pigs and chickens are there if there are 48 heads and 124 feet?
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A farmer counts 70 heads and 200 legs how many chickens and pigs does he have?
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2 monkeys four pigs three chickens have how many legs?
2 monkeys = 4 legs 4 pigs = 16 legs 3 chickens = 6 legs 26 legs total
Two monkeys 4 pigs and 3 chickens have how many legs?
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If you have 2 monkeys 4 pigs 3 chickens how many legs are there?
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