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How so you solve parentheses x-4 closed parentheses squared equals negative 36?
Wiki User
∙ 14y ago
Just take the square root of each side.
(x-4)2 = -36
x - 4 = (plus or minus) 6i
This gives two solutions:
x - 4 = 6i
x = 4 + 6i
and:
x - 4 = -6i
x = 4 - 6i
If you want only real numbers, then of course the equation has no solution. For some problems, complex numbers may be acceptable, for others, not.
Just take the square root of each side.
(x-4)2 = -36
x - 4 = (plus or minus) 6i
This gives two solutions:
x - 4 = 6i
x = 4 + 6i
and:
x - 4 = -6i
x = 4 - 6i
If you want only real numbers, then of course the equation has no solution. For some problems, complex numbers may be acceptable, for others, not.
Just take the square root of each side.
(x-4)2 = -36
x - 4 = (plus or minus) 6i
This gives two solutions:
x - 4 = 6i
x = 4 + 6i
and:
x - 4 = -6i
x = 4 - 6i
If you want only real numbers, then of course the equation has no solution. For some problems, complex numbers may be acceptable, for others, not.
Just take the square root of each side.
(x-4)2 = -36
x - 4 = (plus or minus) 6i
This gives two solutions:
x - 4 = 6i
x = 4 + 6i
and:
x - 4 = -6i
x = 4 - 6i
If you want only real numbers, then of course the equation has no solution. For some problems, complex numbers may be acceptable, for others, not.
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoJust take the square root of each side.
(x-4)2 = -36
x - 4 = (plus or minus) 6i
This gives two solutions:
x - 4 = 6i
x = 4 + 6i
and:
x - 4 = -6i
x = 4 - 6i
If you want only real numbers, then of course the equation has no solution. For some problems, complex numbers may be acceptable, for others, not.
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