3a-9 = 6
3a = 6+9
3a = 15
a = 15/3
a = 5
Substitute a = 5 into 4a-1.
4a-1
=4(5)-1
=20-1
=19
Therefore, the value of 4a-1 is 19.
4a + 1 - a =19, rewrite your question, 4a + -a + 1 =19, 3a + 1 =19, subtract 1 from each side 3a = 18, divide by 3, a =6
If your problem looks like this: 4a-a=_ the answer is... 3a
3a = 1a = 1/3 (a third)
5a - 1 = a - 7 4a = -6 a = -1.5
4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3
4a + 1 - a =19, rewrite your question, 4a + -a + 1 =19, 3a + 1 =19, subtract 1 from each side 3a = 18, divide by 3, a =6
7a-17 = 4a+1 7a-4a = 1+17 3a = 18 a = 6
3a=1divide both sides by 3a=1/3
If your problem looks like this: 4a-a=_ the answer is... 3a
3a2
Clearly, there are some signs missing. So let's try the four possibilities for the second terms: 1. + and + 3a + 4b = 7a + 4b Subtract 4b from each side: 3a = 7a Subtract 3a from each side: 0 = 4a Answer : a = 0, b indeterminate (ie can have any vaue). 2. + and - 3a + 4b = 7a - 4b Subtract 4b from each side: 3a = 7a - 8b Subtract 7a from each side: -4a = -8b or 4a = 8b Answer: a = 2b 3. - and - 3a - 4b = 7a - 4b Add 4b to each side: 3a = 7a Subtract 3a from each side: 0 = 4a Answer : a = 0, b indeterminate (ie can have any vaue). 4. - and + 3a - 4b = 7a + 4b Add 4b to each side: 3a = 7a + 8b Subtract 7a from each side: -4a = 8b or 4a = -8b Answer: a = -2b Can't do better than that with the information available.
It is: 7a+1 when simplified
3a = 1a = 1/3 (a third)
5a - 1 = a - 7 4a = -6 a = -1.5
1/2
9=4a+13 9-13=4a -4=4a -4/4=a -1=a a=-1
4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3