G - 5 = -9; G - 5 + 5 = -9 + 5; G = -4; to prove the answer, substitute -4 for G.
G - 5 = -9. We need to find the value of G in the above equation. To find the value of G, we need to isolate G. To isolate G, we have to kill -5 on the left hand side of the equation. To kill -5, we need to add +5 on both the sides of the equation. That implies G -5 + 5 = -9 + 5 G + 0 = -4 G = -4.
5 kg = 5000 g5 kg = 5000 g5 kg = 5000 g5 kg = 5000 g5 kg = 5000 g5 kg = 5000 g
14
This is a ditloid. The answer is 9 = gallons in a firkin.
1 g = 1000 mg so 9 g = 9000 mg
-3g+6+2g=15 -g=9 g=-9
9g + 2 = 39g = 1g = 1/9 = 0.111111111
'kilo' means 1000.
2g - 9 = -5 Therefore, 2g = 4 Therefore, g = 4/2 g = 2
1 kg = 1000 g so 1/1000 kg = 1 g so there are (1/1000)/9 lots of 9 kg = 0.000111... lots of 9 kg in 1 g
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