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This is a ditloid. The answer is 9 = gallons in a firkin.

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11y ago
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Q: What is 9 equals G in a F?
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Related questions

If c varies jointly as f and g and c equals 27 and f equals 18 and g equals 6 find c when f equals 30 and g equals 10?

x = 75


F varies jointly as g h and j One set of values is f equals 18 g equals 4 h equals 3 and j equals 5 Find f when g equals 5 h equals 12 and j equals 3?

f = 54


When f of g of x equals x?

f and g are inverse functions.


What does f equals in 9-f equals 17?

-8


If f of x equals x plus 1 and g of f of x equals x what is g of x?

f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1


Assume f of x equals 4x plus 8 and g of x equals 5 What is the value of g o f-1?

g(x) = 5. So whatever f(x) or f(-1) is, g of that is going to be 5.


G - 5 equals -9?

14


If f of x equals g of x does f prime of x equal g prime of x?

Yes


If hx equals f o g x and hx equals sqrt x plus 5 find gx if fx equals sqrt x plus 2?

g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)


What is the domain of the function G of F of x when F of x equals 8 minus x G of y equals square root of y G of F of x equals square root of 8 minus x?

x


What is the derivative of f plus g of 3 and f times g of 3 given that f of 3 equals 5 d dx f of 3 equals 1.1 g of 3 equals -4 d dx g of 3 equals 7 Also please explain QUICK THANK YOU?

d/dx [f(x) + g(x)] = d/dx [f(x)] + d/dx [g(x)] or f'(x) + g'(x) when x = 3, d/dx [f(x) + g(x)] = f'(3) + g'(3) = 1.1 + 7 = 8.1 d/dx [f(x)*g(x)] = f(x)*d/dx[g(x)] + d/dx[f(x)]*g(x) when x = 3, d/dx [f(x)*g(x)] = f(3)*g'(3) + f'(3)*g(3) = 5*7 + 1.1*(-4) = 35 - 4.4 = 31.1


Is f plus g equals 3 commutative property?

No, by itself it is not.