14
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
12f -9 = 27 12f = 27+9 12f = 36 f = 3
wth??
It would be 7.
x = 75
f = 54
f and g are inverse functions.
-8
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
g(x) = 5. So whatever f(x) or f(-1) is, g of that is going to be 5.
14
Yes
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
x
d/dx [f(x) + g(x)] = d/dx [f(x)] + d/dx [g(x)] or f'(x) + g'(x) when x = 3, d/dx [f(x) + g(x)] = f'(3) + g'(3) = 1.1 + 7 = 8.1 d/dx [f(x)*g(x)] = f(x)*d/dx[g(x)] + d/dx[f(x)]*g(x) when x = 3, d/dx [f(x)*g(x)] = f(3)*g'(3) + f'(3)*g(3) = 5*7 + 1.1*(-4) = 35 - 4.4 = 31.1
No, by itself it is not.